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Chemistry
Chemistry
Problem
K
a
K_a
K
a
for HCN and
CH
3
COOH
\text{CH}_3\text{COOH}
CH
3
COOH
are
4.9
×
10
−
10
4.9 \times 10^{-10}
4.9
×
1
0
−
10
and
1.8
×
10
−
5
1.8 \times 10^{-5}
1.8
×
1
0
−
5
respectively. Calculate the equilibrium constant for the reaction:
CH
3
COOH
+
NaCN
⇌
CH
3
COONa
+
HCN
\text{CH}_3\text{COOH} + \text{NaCN} \rightleftharpoons \text{CH}_3\text{COONa} + \text{HCN}
CH
3
COOH
+
NaCN
⇌
CH
3
COONa
+
HCN
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