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Mathematics
Mathematics
Problem
2
(
x
−
3
)
2
−
b
=
0
2(x-3)^2 - b = 0
2
(
x
−
3
)
2
−
b
=
0
In the equation above,
b
b
b
is a constant. If the equation has the solutions
x
=
3
±
5
x = 3 \pm \sqrt{5}
x
=
3
±
5
, what is the value of
b
b
b
?
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