Mathematics

Mathematics

Problem

If −1<x<0-1 < x < 0, then sin⁡−1x\sin^{-1}x equals (a) π−cos⁡−1(1−x2)\pi - \cos^{-1}(\sqrt{1-x^2}) (b) tan⁡−1x1−x2\tan^{-1}\frac{x}{\sqrt{1-x^2}} (c) −cot⁡−1(1−x2x)-\cot^{-1}\left(\frac{\sqrt{1-x^2}}{x}\right) (d) csc⁡−1x\csc^{-1}x

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