Physics

Problem

21N.2.SL.TZ0.4 A charged particle, P, of charge

+68\ \mu\text{C}

is fixed in space. A second particle, Q, of charge

+0.25\ \mu\text{C}

is held at a distance of 48 cm from P and is then released. The diagram shows two parallel wires X and Y that carry equal currents into the page. Point Q is equidistant from the two wires. The magnetic field at Q due to wire X alone is 15 mT. a. The work done to move a particle of charge

0.25\ \mu\text{C}

from one point in an electric field to another is

4.5\ \mu\text{J}

. Calculate the magnitude of the potential difference between the two points. [1] b.i. Determine the force on Q at the instant it is released. [2] b.ii. Describe the motion of Q after release. [2] c.i. On the diagram draw an arrow to show the direction of the magnetic field at Q due to wire X alone. [1] c.ii. Determine the magnitude and direction of the resultant magnetic field at Q. [2]

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