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Mathematics
Mathematics
Problem
Let
F
(
x
)
=
∫
(
6
x
2
−
8
cos
x
+
10
e
x
)
d
x
F(x)=\displaystyle\int \bigl(6x^{2}-8\cos x+10e^{x}\bigr)\,dx
F
(
x
)
=
∫
(
6
x
2
−
8
cos
x
+
10
e
x
)
d
x
and suppose
F
(
0
)
=
7
F(0)=7
F
(
0
)
=
7
. Find the value of
F
(
1
)
F(1)
F
(
1
)
. a)
10
e
+
8
sin
1
−
1
10e + 8\sin 1 - 1
10
e
+
8
sin
1
−
1
b)
10
e
−
8
cos
1
−
1
10e - 8\cos 1 - 1
10
e
−
8
cos
1
−
1
c)
10
e
−
8
sin
1
−
1
10e - 8\sin 1 - 1
10
e
−
8
sin
1
−
1
d)
10
e
−
8
sin
1
−
3
10e - 8\sin 1 - 3
10
e
−
8
sin
1
−
3
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