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Mathematics
Problem
A bacterial population is modeled by
P
(
t
)
=
k
t
3
/
2
P(t)=k t^{3/2}
P
(
t
)
=
k
t
3/2
, where
t
t
t
is measured in days and
k
k
k
is a positive constant. When
t
=
4
t=4
t
=
4
, the population is 320 bacteria. Determine the instantaneous rate of growth of the population at
t
=
9
t=9
t
=
9
days.
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