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Chemistry
Chemistry
Problem
log
e
K
\log_e K
lo
g
e
K
vs.
1
/
T
1/T
1/
T
plots show a straight line having slope of
120
∘
120^\circ
12
0
∘
and intercepts on the
Y
Y
Y
-axis of 2, then : a.
E
a
=
8.0
cal
E_a = 8.0 \text{ cal}
E
a
=
8.0
cal
,
A
=
100
A = 100
A
=
100
b.
E
a
=
8.0
cal
E_a = 8.0 \text{ cal}
E
a
=
8.0
cal
,
A
=
2
A = 2
A
=
2
c.
E
a
=
3.46
cal
E_a = 3.46 \text{ cal}
E
a
=
3.46
cal
,
A
=
7.38
A = 7.38
A
=
7.38
d.
E
a
=
3.46
cal
E_a = 3.46 \text{ cal}
E
a
=
3.46
cal
,
A
=
100
A = 100
A
=
100
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