Physics

Physics

Problem

In the reaction 11H+13H→24He+01n^1_1\text{H} + ^3_1\text{H} \rightarrow ^4_2\text{He} + ^1_0\text{n} , if binding energies of 11H^1_1\text{H} , 13H^3_1\text{H} and 24He^4_2\text{He} are respectively aa , bb and cc (in MeV), then the energy released in this reaction is: a. a+b+ca + b + c b. a+b−ca + b - c c. c−(a+b)c - (a + b) d. c+a−bc + a - b

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