Physics

Physics

Problem

A horizontal upper plate of a capacitor is suspended by a spring of spring constant k=100 N/mk = 100\,\text{N/m}. The lower plate is fixed. The area of the plates is A=0.01 m2A = 0.01\,\text{m}^{2}. When the capacitor is uncharged, the separation is d=5 mmd = 5\,\text{mm}. A voltage VV is applied, causing the upper plate to move down by 1 mm1\,\text{mm} in equilibrium. Calculate the value of VV. (Take ε0=8.85×10−12 F/m\varepsilon_{0} = 8.85 \times 10^{-12}\,\text{F/m}).

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