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Chemistry
Chemistry
Problem
The value of
K
P
K_P
K
P
for dissociation of
2
H
I
⇌
H
2
+
I
2
2HI \rightleftharpoons H_2 + I_2
2
H
I
⇌
H
2
+
I
2
is
1.84
×
10
−
2
1.84 \times 10^{-2}
1.84
×
1
0
−
2
. If the equilibrium concentration of
H
2
H_2
H
2
is
0.4789
mol litre
−
1
0.4789 \text{ mol litre}^{-1}
0.4789
mol litre
−
1
, calculate the concentration of HI at equilibrium.
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