Mathematics

Mathematics

Problem

The general solution of 8tan⁡2x2=1+sec⁡x8 \tan^2 \frac{x}{2} = 1 + \sec x is a. x=2nπ±cos⁡−1(−13)x = 2n\pi \pm \cos^{-1}\left(\frac{-1}{3}\right) b. x=2nπ±π6x = 2n\pi \pm \frac{\pi}{6} c. x=2nπ±cos⁡−1(13)x = 2n\pi \pm \cos^{-1}\left(\frac{1}{3}\right) d. None of these

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