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Mathematics
Mathematics
Problem
Define
h
(
x
)
=
x
2
+
1
csc
x
h(x)=\dfrac{x^{2}+1}{\csc x}
h
(
x
)
=
csc
x
x
2
+
1
for
0
<
x
<
π
0<x<\pi
0
<
x
<
π
. (a) Determine
h
′
(
x
)
h'(x)
h
′
(
x
)
. (b) Evaluate
h
′
(
π
4
)
h'\!\left(\dfrac{\pi}{4}\right)
h
′
(
4
π
)
and express your answer in exact form.
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