Complex Analysis: Theory and Applications · Problem 5.1.11

Elementary Functions — Howell & Matthews

Mathematics — Complex Analysis · complex-exponential-limits

Problem

Verify that ((a)) lim⁡z→0ez−1z=1\lim_{z\to 0} \dfrac{e^z - 1}{z} = 1. ((b)) lim⁡z→iπez+1z−iπ=−1\lim_{z\to i\pi} \dfrac{e^z + 1}{z - i\pi} = -1.

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