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Problem
Problem
If
x
=
log
λ
a
=
log
a
b
=
1
2
log
b
c
x = \log_\lambda a = \log_a b = \frac{1}{2} \log_b c
x
=
lo
g
λ
a
=
lo
g
a
b
=
2
1
lo
g
b
c
and
log
λ
c
=
n
x
n
+
1
,
the value of
n
is
\log_\lambda c = nx^{n+1}, \text{ the value of } n \text{ is}
lo
g
λ
c
=
n
x
n
+
1
,
the value of
n
is
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