a) If f:[0,1]→R is given by f(x):=xm for an integer m≥0, show f is Lipschitz and find the best (the smallest) Lipschitz constant K (depending on m of course). Hint: (x−y)(xm−1+xm−2y+xm−3y2+⋯+xym−2+ym−1)=xm−ym.
b) Using the previous exercise, show that if f:[0,1]→R is a polynomial, that is, f(x):=amxm+am−1xm−1+⋯+a0, then f is Lipschitz.