General Relativity: An Introduction for Physicists · Problem 13.20

The Kerr geometry — Hobson, Efstathiou & Lasenby

Physics · kerr-photon-orbit-rdot-squared

Problem

For a photon orbit in the equatorial plane of the Kerr geometry, show that r˙2=(r2+a2)2−a2Δc2r4[c2k−V+(r)][c2k−V−(r)],\dot{r}^2 = \frac{(r^2 + a^2)^2 - a^2\Delta}{c^2 r^4}\left[c^2k - V_+(r)\right]\left[c^2k - V_-(r)\right], where V±(r)=2μra±r2Δ1/2(r2+a2)2−a2Δ ch=[ω±(ω2−gϕϕgtt)1/2]h.V_{\pm}(r) = \frac{2\mu r a \pm r^2 \Delta^{1/2}}{(r^2 + a^2)^2 - a^2\Delta}\, ch = \left[\omega \pm \left(\omega^2 - \frac{g^{\phi\phi}}{g^{tt}}\right)^{1/2}\right]h.

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