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Mathematics
Problem
If
(
x
−
1
)
(
x
2
+
1
)
>
0
(x-1)(x^2+1) > 0
(
x
−
1
)
(
x
2
+
1
)
>
0
, then
sin
(
1
2
tan
−
1
2
x
1
−
x
2
−
tan
−
1
x
)
\sin\left(\frac{1}{2} \tan^{-1} \frac{2x}{1-x^2} - \tan^{-1} x\right)
sin
(
2
1
tan
−
1
1
−
x
2
2
x
−
tan
−
1
x
)
is equal to a. 1 b.
1
2
\frac{1}{\sqrt{2}}
2
1
c.
−
1
-1
−
1
d. None of these
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