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Problem If A = 2 x cot x x A = \frac{2^x \cot x}{\sqrt{x}} A = x 2 x c o t x , then d A d x = \frac{dA}{dx} = d x d A =
(a) 2 x − 1 { − 2 x cosec 2 x + cot x ⋅ log ( 4 x e ) } x 3 / 2 \frac{2^{x-1} \left\{ -2x \operatorname{cosec}^2 x + \cot x \cdot \log \left( \frac{4^x}{e} \right) \right\}}{x^{3/2}} x 3/2 2 x − 1 { − 2 x cosec 2 x + c o t x ⋅ l o g ( e 4 x ) }
(b) 2 x − 1 { − 2 x cosec 2 x + cot x ⋅ log ( 4 x e ) } x \frac{2^{x-1} \left\{ -2x \operatorname{cosec}^2 x + \cot x \cdot \log \left( \frac{4^x}{e} \right) \right\}}{x} x 2 x − 1 { − 2 x cosec 2 x + c o t x ⋅ l o g ( e 4 x ) }
(c) 2 x { − 2 x cosec 2 x + cot x ⋅ log ( 4 x e ) } x 3 / 2 \frac{2x \left\{ -2x \operatorname{cosec}^2 x + \cot x \cdot \log \left( \frac{4^x}{e} \right) \right\}}{x^{3/2}} x 3/2 2 x { − 2 x cosec 2 x + c o t x ⋅ l o g ( e 4 x ) }
(d) None of these
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