Griffiths Introduction to Elementary Particles · Problem 5.12

The Feynman Calculus — David J. Griffiths

Physics — QFT · expectation-value-tensor-operator

Problem

Suppose A\mathbf{A} and B\mathbf{B} are two fixed vectors. Show that the expectation value of Q≡[3(A⋅r^)(B⋅r^)−(A⋅B)]Q \equiv [3(\mathbf{A}\cdot\hat{r})(\mathbf{B}\cdot\hat{r}) - (\mathbf{A}\cdot\mathbf{B})] is zero in any spherically symmetrical state. [Hint: First convince yourself that ⟨Q⟩\langle Q \rangle must be proportional to (A⋅B)(\mathbf{A}\cdot\mathbf{B}): ⟨Q⟩=α(A⋅B)\langle Q \rangle = \alpha(\mathbf{A}\cdot\mathbf{B}) where α\alpha, the proportionality constant, is independent of A\mathbf{A} and B\mathbf{B}. To evaluate α\alpha, take the case where A\mathbf{A} and B\mathbf{B} are parallel, and choose the zz axis to lie along this direction. Then α=⟨(3cos⁡2θ−1)⟩\alpha = \langle (3\cos^2\theta - 1) \rangle Now perform the θ\theta integral. [Notice that the argument is not affected if an arbitrary function of rr is thrown into the expectation value. In particular, the expectation value of the first term in equation (5.59) must vanish for an electron in the SS state.]]

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