Mathematics

Mathematics

Problem

Consider the limit L=lim⁡x→01−cos⁡(4x)x2.L=\lim_{x\to 0}\frac{1-\cos(4x)}{x^2}. The expression appears to be indeterminate of the form 00\tfrac00. a. Verify algebraically that 1−cos⁡(4x)=2sin⁡2(2x).1-\cos(4x)=2\sin^2(2x). b. Rewrite LL entirely in terms of sin⁡(2x)\sin(2x) and xx, showing each algebraic step clearly. c. Explain, without using L’Hôpital’s Rule, why the form obtained in part (b) guarantees that LL approaches a finite, non-zero value as x→0x\to0. State that value explicitly.

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