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Mathematics
Mathematics
Problem
Let
y
(
x
)
y(x)
y
(
x
)
be the solution of the differential equation
(
x
log
x
)
d
y
d
x
+
y
=
2
x
log
x
,
(
x
≥
1
)
(x \log x) \frac{dy}{dx} + y = 2x \log x, (x \ge 1)
(
x
lo
g
x
)
d
x
d
y
+
y
=
2
x
lo
g
x
,
(
x
≥
1
)
. Then
y
(
e
)
y(e)
y
(
e
)
is equal to: (1)
e
e
e
(2) 0 (3) 2 (4)
2
e
2e
2
e
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