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Mathematics
Mathematics
Problem
For
f
(
x
)
=
x
2
−
16
x
−
4
f(x)=\dfrac{x^{2}-16}{x-4}
f
(
x
)
=
x
−
4
x
2
−
16
when
x
≠
4
x\ne4
x
=
4
and
f
(
4
)
=
7
f(4)=7
f
(
4
)
=
7
, which kind of discontinuity existed at
x
=
4
x=4
x
=
4
before the value of
f
(
4
)
f(4)
f
(
4
)
was specified? a) Jump discontinuity b) Removable discontinuity c) Infinite discontinuity d) No discontinuity (function is continuous)
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