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Physics
Physics
Problem
If a semiconductor photodiode can detect a photon with a maximum wavelength of 400 nm, then its band gap energy is: Planck's constant,
h
=
6.63
×
10
−
34
h = 6.63 \times 10^{-34}
h
=
6.63
×
1
0
−
34
J.s. Speed of light,
c
=
3
×
10
8
c = 3 \times 10^8
c
=
3
×
1
0
8
m/s a. 1.1 eV b. 2.0 eV c. 1.5 eV d. 3.1 eV
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