In Problem 2, show that xk=(sinkπh,sin2kπh,…,sinnkπh) is an eigenvector of A. Multiply xk by A to find the corresponding eigenvalue αk. Verify that in the 3 by 3 case these eigenvalues are 2−2, 2, 2+2.
Note. The eigenvalues of the Jacobi matrix J=21(−L−U)=I−21A are λk=1−21αk=coskπh. They occur in plus-minus pairs and λmax is cosπh.