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Mathematics
Mathematics
Problem
If
P
=
θ
:
sin
θ
−
cos
θ
=
2
cos
θ
P = {\theta : \sin \theta - \cos \theta = \sqrt{2} \cos \theta}
P
=
θ
:
sin
θ
−
cos
θ
=
2
cos
θ
and
Q
=
θ
:
sin
θ
+
cos
θ
=
2
sin
θ
Q = {\theta : \sin \theta + \cos \theta = \sqrt{2} \sin \theta}
Q
=
θ
:
sin
θ
+
cos
θ
=
2
sin
θ
be two sets, then, a.
P
⊂
Q
P \subset Q
P
⊂
Q
and
Q
−
P
≠
∅
Q - P \neq \emptyset
Q
−
P
=
∅
b.
Q
⊂
P
Q \subset P
Q
⊂
P
c.
P
⊄
Q
P \not\subset Q
P
⊂
Q
d.
P
=
Q
P = Q
P
=
Q
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