Two coupled, identical rotators are described by the Hamiltonian
H=A(pΘ12+pΘ22)−Bcos(Θ1−Θ2),
where A and B>0, pΘi=(ℏ/i)∂/∂Θi, and Θi+2π is equivalent to Θi. For the case B≪Aℏ2, calculate the energy eigenvalues using perturbation theory. In the opposite case B≫Aℏ2, assume that only small oscillations occur, and construct the solution in analogy to the harmonic oscillator. Hint: Introduce new variables x=Θ1+Θ2 and y=Θ1−Θ2. In terms of these variables, the Hamiltonian becomes
H=−2Aℏ2(∂x2∂2+∂y2∂2)−Bcosy.