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Mathematics
Problem
Let
f
(
x
)
f(x)
f
(
x
)
is an odd function defined on
R
\mathbb{R}
R
such that
f
(
1
)
=
2
f(1)=2
f
(
1
)
=
2
,
f
(
3
)
=
5
f(3)=5
f
(
3
)
=
5
and
f
(
−
5
)
=
−
1
f(-5)=-1
f
(
−
5
)
=
−
1
. The value of
f
(
f
(
f
(
−
3
)
)
)
+
f
(
f
(
0
)
)
3
f
(
1
)
−
2
f
(
3
)
−
f
(
5
)
\frac{f(f(f(-3))) + f(f(0))}{3f(1) - 2f(3) - f(5)}
3
f
(
1
)
−
2
f
(
3
)
−
f
(
5
)
f
(
f
(
f
(
−
3
)))
+
f
(
f
(
0
))
is
−
2
3
\frac{-2}{3}
3
−
2
−
2
5
\frac{-2}{5}
5
−
2
2
5
\frac{2}{5}
5
2
2
3
\frac{2}{3}
3
2
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