Mathematics

Mathematics

Problem

Let x(t)=22(cos⁡t)sin⁡2tx(t) = 2\sqrt{2}(\cos t)\sqrt{\sin 2t} and y(t)=22(sin⁡t)sin⁡2ty(t) = 2\sqrt{2}(\sin t)\sqrt{\sin 2t} , t∈(0,π2)t \in (0, \frac{\pi}{2}) . Then 1+(dydx)2dydx at t=π4 is equal to\frac{1 + \left(\frac{dy}{dx}\right)^2}{\frac{dy}{dx}} \text{ at } t = \frac{\pi}{4} \text{ is equal to}

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