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Chemistry
Chemistry
Problem
The total number of ions present in 1 mL of 0.1 M barium nitrate
B
a
(
N
O
3
)
2
Ba(NO_3)_2
B
a
(
N
O
3
)
2
solution is 1)
6.02
×
10
18
6.02 \times 10^{18}
6.02
×
1
0
18
2)
6.02
×
10
19
6.02 \times 10^{19}
6.02
×
1
0
19
3)
3.0
×
6.02
×
10
19
3.0 \times 6.02 \times 10^{19}
3.0
×
6.02
×
1
0
19
4)
3.0
×
6.02
×
10
18
3.0 \times 6.02 \times 10^{18}
3.0
×
6.02
×
1
0
18
1)
6.02
×
10
18
6.02 \times 10^{18}
6.02
×
1
0
18
2)
6.02
×
10
19
6.02 \times 10^{19}
6.02
×
1
0
19
3)
3.0
×
6.02
×
10
19
3.0 \times 6.02 \times 10^{19}
3.0
×
6.02
×
1
0
19
4)
3.0
×
6.02
×
10
18
3.0 \times 6.02 \times 10^{18}
3.0
×
6.02
×
1
0
18
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