If f(x)={⌊1−4x2⌋,0≤x<1⌊x2−2x⌋,1≤x<2f(x) = \begin{cases} \lfloor 1 - 4x^2 \rfloor, & 0 \le x < 1 \\ \lfloor x^2 - 2x \rfloor, & 1 \le x < 2 \end{cases}…

Mathematics

Problem

If f(x)={⌊1−4x2⌋,0≤x<1⌊x2−2x⌋,1≤x<2f(x) = \begin{cases} \lfloor 1 - 4x^2 \rfloor, & 0 \le x < 1 \\ \lfloor x^2 - 2x \rfloor, & 1 \le x < 2 \end{cases}, where ⌊ ⌋\lfloor\ \rfloor denotes the greatest integer function, then a. f(x)f(x) is continuous for all x∈[0,2]x \in [0, 2] b. f(x)f(x) is differentiable for all x∈[0,2]−{1}x \in [0, 2] - \{1\} c. f(x)f(x) is differentiable for all x∈[0,2]−{12,1}x \in [0, 2] - \left\{\frac{1}{2}, 1\right\} d. None of these

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