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Problem
Problem
If
A
=
[
1
2
−
1
2
1
2
−
1
1
1
]
A = \begin{bmatrix} 1 & 2 & -1 \\ 2 & 1 & 2 \\ -1 & 1 & 1 \end{bmatrix}
A
=
1
2
−
1
2
1
1
−
1
2
1
, then
det
(
adj
(
adj
A
)
)
\det(\text{adj }(\text{adj } A))
det
(
adj
(
adj
A
))
is a.
14
4
14^4
1
4
4
b.
14
3
14^3
1
4
3
c.
14
2
14^2
1
4
2
d. 14
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