Chemistry

Problem

When a balanced chemical equation is written in the reverse direction, how is the new reaction quotient

Q_{\text{rev}}

related to the reaction quotient

Q_{\text{fwd}}

for the original orientation, assuming the same set of species concentrations? a)

Q_{\text{rev}} = (Q_{\text{fwd}})^2

Q_{\text{rev}} = Q_{\text{fwd}}

Q_{\text{rev}} = \dfrac{1}{Q_{\text{fwd}}}

Q_{\text{rev}} = \dfrac{1}{(Q_{\text{fwd}})^2}