Physics

Physics

Problem

An industrial freezer is set to an ambient temperature of −20∘C-20^{\circ}\text{C}. A container of hot liquid at 80∘C80^{\circ}\text{C} is placed inside. The temperature T(t)T(t) follows Newton's Law of Cooling: T(t)=(Tinitial−Tambient)e−rt+TambientT(t) = (T_{\text{initial}} - T_{\text{ambient}}) e^{-rt} + T_{\text{ambient}}. If the decay rate constant rr is 0.1 min−10.1\,\text{min}^{-1}, calculate the temperature of the liquid after 1010 minutes. (Use e−1≈0.368e^{-1} \approx 0.368)

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