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Chemistry
Chemistry
Problem
For the Brackett series (
n
1
=
4
n_1 = 4
n
1
=
4
) in hydrogen, an electron falls from
n
2
=
7
n_2 = 7
n
2
=
7
. Determine the longest wavelength (in
μ
m
\mu\text{m}
μ
m
) that can be emitted under this condition. a)
2.62
μ
m
2.62\,\mu\text{m}
2.62
μ
m
b)
4.44
μ
m
4.44\,\mu\text{m}
4.44
μ
m
c)
4.05
μ
m
4.05\,\mu\text{m}
4.05
μ
m
d)
2.16
μ
m
2.16\,\mu\text{m}
2.16
μ
m
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