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JEE Advanced 2016 Paper 2 Mathematics Q11
Mathematics
Problem
Let
a
,
b
∈
R
a,b\in\mathbb R
a
,
b
∈
R
and
a
2
+
b
2
≠
0
a^2+b^2\ne0
a
2
+
b
2
=
0
. Suppose
S
=
{
z
∈
C
:
z
=
1
a
+
i
b
t
,
t
∈
R
,
t
≠
0
}
S=\left\{z\in\mathbb C:z=\dfrac{1}{a+ibt},\ t\in\mathbb R,\ t\ne0\right\}
S
=
{
z
∈
C
:
z
=
a
+
ib
t
1
,
t
∈
R
,
t
=
0
}
, where
i
=
−
1
i=\sqrt{-1}
i
=
−
1
. If
z
=
x
+
i
y
z=x+iy
z
=
x
+
i
y
and
z
∈
S
z\in S
z
∈
S
, then
(
x
,
y
)
(x,y)
(
x
,
y
)
lies on
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