Classical Electrodynamics · Problem 10.9

Radiating Systems, Multipole Fields and Radiation — John David Jackson

Physics — E&M · scattering-near-critical-point-rayleigh-failure

Problem

In the scattering of light by a gas very near the critical point the scattered light is observed to be ``whiter'' (i.e., its spectrum is less predominantly peaked toward the blue) than far from the critical point. Show that this can be understood by the fact that the volumes of the density fluctuations become large enough that Rayleigh's law fails to hold. In particular, consider the lowest order approximation to the scattering by a uniform dielectric sphere of radius aa whose dielectric constant ϵr\epsilon_r differs only slightly from unity. (a) Show that for ka≫1ka \gg 1, the differential cross section is sharply peaked in the forward direction and the total scattering cross section is approximately σ≈π2(ka)2∣ϵr−1∣2a2\sigma \approx \frac{\pi}{2}(ka)^2|\epsilon_r - 1|^2 a^2 with a k2k^2, rather than k4k^4, dependence on frequency. (b) Show that for arbitrary kaka the total cross section to lowest order in (ϵr−1)(\epsilon_r - 1) is the expression given in part a, multiplied by the function F(z)=1+5z−2−72z−4(1−cos⁡2z)−z−3sin⁡2z−4(z−2−z−4)∫02z1−cos⁡tt dtF(z) = 1 + 5z^{-2} - \tfrac{7}{2}z^{-4}(1 - \cos 2z) - z^{-3}\sin 2z - 4(z^{-2} - z^{-4})\int_0^{2z}\frac{1-\cos t}{t}\,dt where z=2kaz = 2ka. [This result is due to Lord Rayleigh, 1914.]

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