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Mathematics
Mathematics
Problem
For a particle moving in space, the acceleration is
a
(
t
)
=
⟨
6
k
t
,
0
,
−
2
⟩
\mathbf{a}(t)=\langle 6kt,0,-2\rangle
a
(
t
)
=
⟨
6
k
t
,
0
,
−
2
⟩
, where
k
k
k
is a constant. Given
v
(
0
)
=
⟨
3
,
0
,
4
⟩
\mathbf{v}(0)=\langle 3,0,4\rangle
v
(
0
)
=
⟨
3
,
0
,
4
⟩
and
v
(
1
)
=
⟨
9
,
0
,
2
⟩
\mathbf{v}(1)=\langle 9,0,2\rangle
v
(
1
)
=
⟨
9
,
0
,
2
⟩
, what is the value of
k
k
k
? a)
3
3
3
b)
2
2
2
c)
1
1
1
d)
3
2
\dfrac{3}{2}
2
3
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