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Mathematics
Problem
Find the equation of the line tangent to the curve
x
2
y
−
y
3
=
10
x^2y-y^3=10
x
2
y
−
y
3
=
10
at the point
(
2
,
1
)
(2,1)
(
2
,
1
)
. Express your answer in point–slope form. a)
y
−
1
=
4
3
(
x
−
2
)
y-1=\dfrac{4}{3}(x-2)
y
−
1
=
3
4
(
x
−
2
)
b)
y
−
1
=
−
1
4
(
x
−
2
)
y-1=-\dfrac{1}{4}(x-2)
y
−
1
=
−
4
1
(
x
−
2
)
c)
y
−
1
=
−
4
(
x
−
2
)
y-1=-4(x-2)
y
−
1
=
−
4
(
x
−
2
)
d)
y
−
1
=
4
(
x
−
2
)
y-1=4(x-2)
y
−
1
=
4
(
x
−
2
)
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