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If
Δ
k
=
∣
1
n
n
2
2
k
n
2
+
n
+
1
n
2
+
n
n
2
n
2
+
n
+
1
n
2
+
n
+
1
∣
\Delta_k = \begin{vmatrix} 1 & n & n^2 \\ 2k & n^2 + n + 1 & n^2 + n \\ n^2 & n^2 + n + 1 & n^2 + n + 1 \end{vmatrix}
Δ
k
=
1
2
k
n
2
n
n
2
+
n
+
1
n
2
+
n
+
1
n
2
n
2
+
n
n
2
+
n
+
1
…
Mathematics
Problem
If
Δ
k
=
∣
1
n
n
2
2
k
n
2
+
n
+
1
n
2
+
n
n
2
n
2
+
n
+
1
n
2
+
n
+
1
∣
\Delta_k = \begin{vmatrix} 1 & n & n^2 \\ 2k & n^2 + n + 1 & n^2 + n \\ n^2 & n^2 + n + 1 & n^2 + n + 1 \end{vmatrix}
Δ
k
=
1
2
k
n
2
n
n
2
+
n
+
1
n
2
+
n
+
1
n
2
n
2
+
n
n
2
+
n
+
1
and
∑
k
=
1
n
Δ
k
=
56
\sum_{k=1}^{n} \Delta_k = 56
∑
k
=
1
n
Δ
k
=
56
, then
n
n
n
is equal to a. 4 b. 6 c. 8 d. None of these
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