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Mathematics
Problem
A student writes:
∫
1
3
2
x
d
x
=
x
2
+
C
∣
1
3
=
9
−
1
+
C
=
8
+
C
\int_1^3 2x\,dx = x^2 + C \big|_1^3 = 9 - 1 + C = 8 + C
∫
1
3
2
x
d
x
=
x
2
+
C
1
3
=
9
−
1
+
C
=
8
+
C
. (i) Identify the error in the above working. (ii) Calculate the correct numerical value of the integral.
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