Physics

Physics

Problem

Ice at −20∘C-20^\circ\text{C} is added to 50 g of water at 40∘C40^\circ\text{C} . When the temperature of the mixture reaches 0∘C0^\circ\text{C} , it is found that 20 g of ice is still unmelted. The amount of ice added to the water was close to (Specific heat of water = 4.2 J/g∘C4.2 \text{ J/g}^\circ\text{C} Specific heat of Ice = 2.1 J/g∘C2.1 \text{ J/g}^\circ\text{C} Heat of fusion of water at 0∘C=334 J/g0^\circ\text{C} = 334 \text{ J/g} ) a. 50g b. 100 g c. 60 g d. 40 g

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