Mathematics

Mathematics

Problem

The slope of the tangent to a curve C:y=y(x)C: y = y(x) at any point (x,y)(x, y) on it is 2e2x−6e−x+92+9e−2x\frac{2e^{2x} - 6e^{-x} + 9}{2 + 9e^{-2x}}. If CC passes through the points (0,12+π22)\left(0, \frac{1}{2} + \frac{\pi}{2\sqrt{2}}\right) and (α,12e2α)\left(\alpha, \frac{1}{2}e^{2\alpha}\right), then eαe^\alpha is equal to [Main July 25, 2022 (I)] (a) 3+23−2\frac{3+\sqrt{2}}{3-\sqrt{2}} (b) 32(3+23−2)\frac{3}{\sqrt{2}} \left( \frac{3+\sqrt{2}}{3-\sqrt{2}} \right) (c) 12(2+12−1)\frac{1}{\sqrt{2}} \left( \frac{\sqrt{2}+1}{\sqrt{2}-1} \right) (d) 2+12−1\frac{\sqrt{2}+1}{\sqrt{2}-1}

Browse the problem library