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Mathematics
Mathematics
Problem
In a quadrilateral
A
B
C
D
ABCD
A
B
C
D
,
A
C
AC
A
C
is the bisector of the
∠
(
A
B
,
A
D
)
\angle (AB, AD)
∠
(
A
B
,
A
D
)
which is
2
π
3
\frac{2\pi}{3}
3
2
π
,
15
∣
A
C
∣
=
3
∣
A
B
∣
=
5
∣
A
D
∣
15|\mathbf{AC}| = 3|\mathbf{AB}| = 5|\mathbf{AD}|
15∣
AC
∣
=
3∣
AB
∣
=
5∣
AD
∣
, then
cos
(
B
A
,
C
D
)
\cos(\mathbf{BA}, \mathbf{CD})
cos
(
BA
,
CD
)
is equal to a.
−
14
7
2
-\frac{\sqrt{14}}{7\sqrt{2}}
−
7
2
14
b.
−
21
7
3
-\frac{\sqrt{21}}{7\sqrt{3}}
−
7
3
21
c.
2
7
\frac{2}{\sqrt{7}}
7
2
d.
2
7
14
\frac{2\sqrt{7}}{14}
14
2
7
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