Introduction to Quantum Mechanics · Problem 4.41

Quantum Mechanics in Three Dimensions — David J. Griffiths

Physics — Quantum Mechanics · spin_commutator

Problem

Determine the commutator of S2S^2 with Sz(1)S_z^{(1)} (where S≡S(1)+S(2)\mathbf{S} \equiv \mathbf{S}^{(1)} + \mathbf{S}^{(2)}). Generalize your result to show that [S2,S(1)]=2iℏ(S(1)×S(2))\left[S^2, \mathbf{S}^{(1)}\right] = 2i\hbar\left(\mathbf{S}^{(1)} \times \mathbf{S}^{(2)}\right). (4.185) Comment: Because Sz(1)S_z^{(1)} does not commute with S2S^2, we cannot hope to find states that are simultaneous eigenvectors of both. In order to form eigenstates of S2S^2 we need linear combinations of eigenstates of Sz(1)S_z^{(1)}. This is precisely what the Clebsch–Gordan coefficients (in Equation 4.183) do for us. On the other hand, it follows by obvious inference from Equation 4.185 that the sum S(1)+S(2)\mathbf{S}^{(1)} + \mathbf{S}^{(2)} does commute with S2S^2, which only confirms what we already knew (see Equation 4.103).

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