The neon lamp is switched on using the scheme shown in the figure. After closing the key, the capacitor will start charging. When the voltage across the capacitor reaches a certain value V, the lamp will light up. The minimum voltage across the lamp at which it is still lit is 80 V, and the current through the lamp is 1 mA. Battery EMF 120 V, 80 V < V < 120 V. At what resistance will the lamp be permanently lit (will not go out)?