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Problem
Show that the area of the parallelogram Formed by the lines x + 3y - a = 0, 3x - 2y + 3a = 0, x + 3y + 4a = 0 and 3x - 2y + 7a = 0 is
20
11
a
2
\frac{20}{11}a^2
11
20
a
2
sq units
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