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Mathematics
Mathematics
Problem
If
6
(
x
−
2
)
2
=
A
x
−
2
+
B
(
x
−
2
)
2
\dfrac{6}{(x-2)^2}=\dfrac{A}{x-2}+\dfrac{B}{(x-2)^2}
(
x
−
2
)
2
6
=
x
−
2
A
+
(
x
−
2
)
2
B
, then
A
A
A
equals a)
6
6
6
b)
−
6
-6
−
6
c)
0
0
0
d)
−
3
-3
−
3
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