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Physics
Physics
Problem
Calculate the altitude above Earth’s surface at which a satellite must be placed so that its period is 24 h. Take
G
=
6.67
×
10
−
11
N m
2
kg
−
2
G = 6.67\times10^{-11}\,\text{N m}^2\text{kg}^{-2}
G
=
6.67
×
1
0
−
11
N m
2
kg
−
2
,
M
E
=
6.0
×
10
24
kg
M_E = 6.0\times10^{24}\,\text{kg}
M
E
=
6.0
×
1
0
24
kg
,
R
E
=
6.4
×
10
6
m
R_E = 6.4\times10^{6}\,\text{m}
R
E
=
6.4
×
1
0
6
m
and
T
=
24
h
T = 24\,\text{h}
T
=
24
h
.
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