Mathematics

Mathematics

Problem

Indicate the correct alternative, if f(x)=x2−1f(x) = \frac{x}{2} - 1 , then on the interval [0,π][0, \pi] , a. tan⁡(f(x))\tan(f(x)) and 1f(x)\frac{1}{f(x)} are both continuous b. tan⁡(f(x))\tan(f(x)) and 1f(x)\frac{1}{f(x)} are both discontinuous c. tan⁡(f(x))\tan(f(x)) and f−1(x)f^{-1}(x) are both continuous d. tan⁡(f(x))\tan(f(x)) is continuous but 1f(x)\frac{1}{f(x)} is not continuous

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