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Mathematics
Mathematics
Problem
If
I
n
=
∫
1
e
(
log
x
)
n
d
x
I_n = \int_1^e (\log x)^n dx
I
n
=
∫
1
e
(
lo
g
x
)
n
d
x
, then
I
n
+
n
I
n
−
1
I_n + nI_{n-1}
I
n
+
n
I
n
−
1
is equal to a.
1
e
\frac{1}{e}
e
1
b.
e
e
e
c.
e
−
1
e - 1
e
−
1
d. None of these
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